How to Calculate Steel Quantity From Drawing Plans
General guidelines to be followed in preparing Bbs:
• The bars should be grouped together for each structural unit, e.thou., beam, etc.
• In a building structure, the bars should be listed floor by floor
• For cutting and bending purposes, schedules should exist provided equally dissever A4 sheets and not equally part of the detailed reinforcement drawings.
• The grade of bar and fabric schedule and the shapes of the bar used should exist in accordance with BS 8666.
• It is preferable that bars should be listed in the schedule in numerical lodge.
• It is essential that the bar marker reference on the characterization attached to a package of bars refers uniquely to a detail grouping or ready of bars of defined length, size, shape, and type used on the chore.
• This is imperative every bit a bar mark reference can then point to a class of bar characteristics. Also, this helps steel fixers and laborers keep runway of the type and number of bars needed to complete a sure work.
Bar Angle Schedule Required Ment Data
Estimation of steel quantity is an essential skill of any civil engineer. Every ceremonious engineer must know the method of calculation of steel quantity from drawing.
Data requires for estimation of steel quantity:
ane) Program, Superlative & Section
Plan PDF Fille
ii) Structural Detail (Slab & Beam)
Structural PDF File
iii) All dimensions must be clear and co-related.
Axle PDF Fille
How to set a Slab BBS?
Nosotros calculated her two parts of caution of BBS as below
i. Slab Axle.
2. Slab.
Slab Beam Bar Bending Schedule
Slab Beam Location
Slab Beam Location PDF File
Here many axle shows. So nosotros calculate TB1 Beam.
TB1 Axle.
Numbers of bars for Stirrups
Suppose the spacing of stirrups is 200 c/c and the length along which they are placed is 14100 mm, nosotros can find the number of confined by the formula below
[ (xiv.100-200) / 200)] + 1 = seventy.5 Nos
Full Num of Stirrups = 71 Nos
Stirrups Cutting Length
Cutting length axle stirrup
90 degree claw:
Length of stirrup = 2 (A + B) + twenty x dia
135 degree hook:
Length of stirrup = two (A + B) + 24 x dia
Length of stirrup = 2 ( (Lenght -ii Comprehend) + (Breadth-two Encompass) + 24 x Dia
Dia of Stirrups.
Length of stirrup = 2 (0.150 + 0.550) + 24 x 8
Length of stirrup = one.592 thousand
Total Weight of Stirrups
Total Weight Stirrups = (No of ring x Cutting Length ) x (Weight dia of confined)
Total Weight Stirrups = ( 71 ten ane.592) x (0.395) = 44.648 kg
We must remember than steel is ductile in nature and is bailiwick to elongation. Hence, the length of a bar is increased when bends or hooks are introduced. Hence, certain deductions are needed to offset this increase in length.
Cutting Length Bar:
Cutting Length = Truthful Length of a bar – Deductions
For 45 degree
Cutting length = Total length – i 10 Dia of bar x No. of bends
Cutting length = (Total Length) +( 2 x L length) + (Lap Length (45 10 d) ) – (2 10 Bend) – (Cover)
Lesser Bar
2 nos bar 16 mm dia
Cutting length = (11.400+2.400+0.200) + ( 2x 0.550) + ( 45 x 16) – ( two x 0.016 ) -(ii x 0.025)
Cutting length = (14.100) + (1.100) + (0.720) – (0.032) – (0.050)
Cutting length = fifteen.838 m
Full weight of lesser bar = No of Bars x Cutting length x Weight of confined
Total weight of bottom bar = 2 ten fifteen.838 x i.580 = 50.048 kg
Top Bar
two nos bar 20 mm dia
Cutting length = (eleven.400+two.400+0.200) + ( 2x 0.550) + ( 45 10 20) – ( 2 x 0.020 ) -(2 10 0.025)
Cutting length = (14.100) + (i.100) + (0.900) – (0.040) – (0.050)
Cut length = 16.010 g
Total weight of peak bar = No of Bars x Cutting length ten Weight of bars
Total weight of pinnacle bar = 2 x 16.010 x 2.469 = 79.057 kg
Total Weight of Beam = Total Weight Stirrups + Total weight of lesser bar + Total weight of superlative bar
Total Weight of Beam = 44.648 kg + 50.048 kg + 79.057 kg = 173.753 kg
Slab Bar Bending Schedule Excel Sheet
Cut Lenght Slab Bar
Cutting Langth of Bar = (Total length) + ( Bentup Bar Langht(0.42 ten d)) +Lap
Expanse ( -ane to 3)/(-A to +B)
For X Management
8 mm Dia 200 mm c/c
No of Bars = (7 /0.2) + 1 = 36.0 Nos. = 36 Nos
Cutting Bar = (0.100+2.400+4.300+i.000+two.800+i.000+0.100) +( 0.42 * (0.125-0.025-0.025)) + 0
Cutting Bar = (11.700) + (0.032) = 11.732 m
Total weight of X direction slab bar = No of Confined x Cutting length x Weight of bars
Full weight of X direction slab bar = 36 x eleven.732 x 0.395 = 166.829 kg
For Y Management
8 mm Dia 200 mm c/c
No of Bars = (11.700/0.200) + 1 = 59.5 Nos. = 60 Nos
Cutting Bar = (0.100+one.800+iii.200+i.800+0.100) +( 0.42 * (0.125-0.025-0.025)) + 0
Cutting Bar = (vii.000) + (0.0315) = 7.032 one thousand
Total weight of Y direction slab bar = No of Confined x Cutting length x Weight of bars
Full weight of Y direction slab bar = threescore x 7.032 x 0.395 = 166.658 kg
Extra Bars
10 mm Dia 200 mm c/c
No of Bars = (eleven.700/0.200) + ane = 59.5 Nos. = 60 Nos
TB2 area A/( – i to +3) = (0.500 + 0.200 + 0.900 ) = 1.600 g
Total weight of TB1 = No of Bars x Cutting length x Weight of Dia bar
Total weight of TB1 = threescore x 1.600 ten 0.616 = 59.136 kg
No of Bars = (7 /0.2) + 1 = 36.0 Nos. = 36 Nos
TB3 area 4 (-A to +B) = (0.700 + 0.200 + ane.250 ) = ii.150 1000
Full weight of TB3 = 36 x 2.150 x 0.616 = 47.678 kg
No of Bars = (7 /0.ii) + i = 36.0 Nos. = 36 Nos
TB5 surface area 1/two (-A to +B) = (1.250 + 0.200 + 1.400 ) = 2.850 m
Full weight of TB5 = 36 x 2.850 ten 0.616 = 63.202 kg
Full weight of Slab = Full weight of X direction slab bar + Full weight of Y direction slab bar + Full weight of TB1 + Total weight of TB3 + Total weight of TB5
Total weight of Slab = 166.829 kg + 166.658 kg + 59.136 kg + 47.678 kg + 63.202 kg = 503.03 kg
How to Summate Slab Steel Quantity from Drawing Excel Sheet
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Source: https://wrengineers.in/how-to-calculate-slab-steel-quantity-from-drawing/
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